# Kilovolt-amp (kVA)

kVA is kilo-volt-ampere. kVA is a unit of apparent power, which is electrical power unit.

1 kilo-volt-ampere is equal to 1000 volt-ampere:

1kVA = 1000VA

1 kilo-volt-ampere is equal to 1000 times 1 volt times 1 ampere:

1kVA = 1000⋅1V⋅1A

## kVA to volt-amps calculation

So The apparent power S in volt-amps (VA) is equal to 1000 times the apparent power S in kilovolt-amps (kVA).

S(VA) =  1000 × S(kVA)

## kVA to kW calculation

So The real power P in kilowatts (kW) is equal to the apparent power S in kilovolt-amps (kVA), times the power factor [PF]

P(kW) =  S(kVA) × PF

#### Example 1

What is the real power in kilowatts when the apparent power is 8 kVA and the power factor is 0.8?

Solution:

P = 8kVA × 0.8 = 6.4kW

#### Example 2

What is the real power in kilowatts when the apparent power is 35 kVA and the power factor is 0.8?

Solution:

P = 35kVA × 0.8 = 28kW

## kVA to watts calculation

So The real power P in watts (W) is equal to 1000 times the apparent power S in kilovolt-amps (kVA), times the power factor PF.

P(W) =  1000 × S(kVA) × PF

#### Example 1

What is the real power in watts when the apparent power is 7 kVA and the power factor is 0.8?

Solution:

P = 1000 × 7kVA × 0.8 = 5600W

#### Example 2

What is the real power in watts when the apparent power is 16 kVA and the power factor is 0.8?

Solution:

P = 1000 × 16kVA × 0.8 = 12800W

## kVA to amps calculation

### Single phase kVA to amps calculation formula

The current I in amps is equal to 1000 times the apparent power S in kilovolt-amps, divided by the voltage V in volts:

I(A) = 1000 × S(kVA) / V(V)

#### Example 1

Question: What is the phase current in amps when the apparent power is 6 kVA and the RMS voltage supply is 110 volts?

Solution:

I = 1000 × 6kVA / 110V = 54.545A

#### Example 2

Question: What is the phase current in amps when the apparent power is 6 kVA and the RMS voltage supply is 120 volts?

Solution:

I = 1000 × 6kVA / 120V = 50A

### 3 phase kVA to amps calculation formula

#### Calculation with line to line voltage

The phase current I in amps (with balanced loads) is equal to 1000 times the apparent power S in kilovolt-amps, divided by the square root of 3 times the line to line RMS voltage VL-L in volts:

I(A) = 1000 × S(kVA) / (3 × VL-L(V) )

#### Example 1

Question: What is the phase current in amps when the apparent power is 3 kVA and the line to line RMS voltage supply is 180 volts?

Solution:

I = 1000 × 3kVA / (3 × 180V) = 9.623A

#### Example 2

Question: What is the phase current in amps when the apparent power is 4 kVA and the line to line RMS voltage supply is 180 volts?

Solution:

I = 1000 × 4kVA / (3 × 180V) = 12.83A

#### Calculation with line to neutral voltage

So The phase current I in amps (with balanced loads) is equal to 1000 times the apparent power S in kilovolt-amps, divided by 3 times the line to neutral RMS voltage VL-N in volts:

I(A) = 1000 × S(kVA) / (3 × VL-N(V) )

#### Example 1

Question: What is the phase current in amps when the apparent power is 5 kVA and the line to neutral RMS voltage supply is 120 volts?

Solution:

I = 1000 × 5kVA / (3 × 120V) = 13.889A

#### Example 2

Question: What is the phase current in amps when the apparent power is 5 kVA and the line to neutral RMS voltage supply is 180 volts?

Solution:

I = 1000 × 5kVA / (3 × 180V) = 9.259A