Illuminance in lux (lx) to electric power in watts (W) calculator and how to calculate.

Enter the illuminance in lux, luminous efficacy in lumens per watt, surface area in square feet / meters or spherical radius in feet / meters and press the *
Calculate* button to get the power in watts:

* the predefined luminous efficacy values are typical / average values.

So The luminous flux *Φ*_{V} in lumens (lm) is equal to 0.09290304 times the illuminance *E*_{v} in lux (lx) times the surface area *A* in square feet (ft^{2}).

*Φ*_{V(lm)} = 0.09290304* *×* E*_{v(lx)}* *×* A*_{(ft}2_{)}

So The power P in watts (W) is equal to the luminous flux *Φ*_{V} in lumens (lm), divided by the luminous efficacy *η* in lumens per watt (lm/W).

*P*_{(W)} = *Φ*_{V(lm)}* */* η*_{(lm/W)}

So the power P in watts (W) is equal to the 0.09290304 times the illuminance *E*_{v} in lux (lx) times the surface area *A* in square feet (ft^{2}), divided by the luminous efficacy *η* in lumens per watt (lm/W).

*P*_{(W)} = 0.09290304* *×* E*_{v(lx)}* *×* A*_{(ft}2_{)} /* η*_{(lm/W)}

So

watts = 0.09290304* *×* *lux* *× (square feet) / (lumens per watt)

or

W = 0.09290304* *×* *lx* *× ft^{2} / (lm/W)

What is the power consumption with illuminance of 40 lux, luminous efficacy of 15 lumens per watt and surface area of 300 square feet?

*P* = 0.09290304* *×* *40 lx* *× 300 ft^{2} / 15 lm/W = 74.32 W

What is the power consumption with illuminance of 60 lux, luminous efficacy of 15 lumens per watt and surface area of 300 square feet?

*P* = 0.09290304* *×* *60 lx* *× 300 ft^{2} / 15 lm/W = 111.48 W

What is the power consumption with illuminance of 100 lux, luminous efficacy of 15 lumens per watt and surface area of 300 square feet?

*P* = 0.09290304* *×* *100 lx* *× 300 ft^{2} / 15 lm/W =185.80 W

The luminous flux *Φ*_{V} in lumens (lm) is equal to the illuminance *E*_{v} in lux (lx) times the surface area *A* in square meters (m^{2}).

*Φ*_{V(lm)} = *E*_{v(lx)}* *×* A*_{(m}2_{)}

The power P in watts (W) is equal to the luminous flux *Φ*_{V} in lumens (lm), divided by the luminous efficacy *η* in lumens per watt (lm/W):

*P*_{(W)} = *Φ*_{V(lm)} /* η*_{(lm/W)}

So the power P in watts (W) is equal to the illuminance *E*_{v} in lux (lx) times the surface area *A* in square meters (m^{2}), divided by the luminous efficacy *η* in lumens per watt (lm/W):

*P*_{(W)} = *E*_{v(lx)}* *×* A*_{(m}2_{)} /* η*_{(lm/W)}

So

watts = lux* *× (square meters) / (lumens per watt)

or

W = lx* *× m^{2} / (lm/W)

What is the power consumption with illuminance of 40 lux, luminous efficacy of 16lumens per watt and surface area of 18 square meters?

*P* = 40 lx* *× 18 m^{2} / 16 lm/W = 45W

What is the power consumption with illuminance of 60 lux, luminous efficacy of 16 lumens per watt and surface area of 18 square meters?

*P* = 60 lx* *× 18 m^{2} / 16 lm/W = 67.5W

What is the power consumption with illuminance of 100 lux, luminous efficacy of 16 lumens per watt and surface area of 18 square meters?

*P* = 100 lx* *× 18 m^{2} / 16 lm/W = 112.5W

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